C (x)2 x+ 3 dan d (x)=x2 +x-2 nilai (cod) - 4...
Jawab:
Penjelasan dengan langkah-langkah:
diketahui :
c(x) = 2x + 3
d(x) = x² + x - 2
ditanyakan :
nilai (cod)(-4) = ...?
penyelesaian :
(cod)(x) = c(d(x))
(cod)(x) = c(x² + x - 2)
(cod)(x) = 2(x² + x - 2) + 3
(cod)(x) = 2x² + 2x - 4 + 3
(cod)(x) = 2x² + 2x - 1
(cod)(-4) = 2(-4)² + 2(-4) - 1 = 2(16) - 8 - 1 = 32 - 9 = 23
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