Matematika Sekolah Menengah Atas C (x)2 x+ 3 dan d (x)=x2 +x-2 nilai (cod) - 4...​

C (x)2 x+ 3 dan d (x)=x2 +x-2 nilai (cod) - 4...​

Jawab:

Penjelasan dengan langkah-langkah:

diketahui :

c(x) = 2x + 3

d(x) = x² + x - 2

ditanyakan :

nilai (cod)(-4) = ...?

penyelesaian :

(cod)(x) = c(d(x))

(cod)(x) = c(x² + x - 2)

(cod)(x) = 2(x² + x - 2) + 3

(cod)(x) = 2x² + 2x - 4 + 3

(cod)(x) = 2x² + 2x - 1

(cod)(-4) = 2(-4)² + 2(-4) - 1 = 2(16) - 8 - 1 = 32 - 9 = 23

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